If $\frac{{{}^{n + 2}{C_6}}}{{{}^{n - 2}{P_2}}} = 11$, then $n$ satisfies the equation
If $\frac{{{}^{n + 2}{C_6}}}{{{}^{n - 2}{P_2}}} = 11$, then $n$ satisfies the equation
- [JEE MAIN 2016]
- A
$n^2 + n - 110 =0$
- B
$n^2 + 2n - 80 =0$
- C
$n^2 +3n- 108=0$
- D
$n^2 + 5n - 84 =0$
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