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3 and 4 .Determinants and Matrices
hard
જો $A = \left[ {\begin{array}{*{20}{c}}
1&0&0 \\
2&1&0 \\
{ - 3}&2&1
\end{array}} \right]\,$ અને $B = \left[ {\begin{array}{*{20}{c}}
1&0&0 \\
{ - 2}&1&0 \\
7&{ - 2}&1
\end{array}} \right]$ તો $AB$ મેળવો.
A
$I$
B
$A$
C
$B$
D
$0$
(AIEEE-2012)
Solution
$A = \left[ {\begin{array}{*{20}{c}}
1&0&0\\
2&1&0\\
{ – 3}&2&1
\end{array}} \right],B = \left[ {\begin{array}{*{20}{c}}
1&0&0\\
{ – 2}&1&0\\
7&{ – 2}&1
\end{array}} \right]$
$AB = \left[ {\begin{array}{*{20}{c}}
1&0&0\\
0&1&0\\
0&0&1
\end{array}} \right] = I$
Standard 12
Mathematics