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6.Permutation and Combination
normal
If $'n'$ objects are arranged in a row then the number of ways of selecting three of these objects so that no two of them are next to each othe
A
${}^{n - 2}{C_3}$
B
${}^{n - 2}{C_2}$
C
${}^{n - 3}{C_3}$
D
None
Solution
Number of ways of selection of $^{\prime} 3^{\prime}$
$=$ Number of ways to put 3 in $(n-2)$ gapes
$=^{n-2} C_{3}$
Standard 11
Mathematics