- Home
- Standard 11
- Physics
5.Work, Energy, Power and Collision
normal
If $F = 2x^2 -3x -2$, then choose correct option
A
$x = -1/2$ is position of stable equilibrium
B
$x = 2$ is position of stable equilibrium
C
$x = -1/2$ is position of unstable equilibrium
D
$x = 2$ is position of neutral equilibrium
Solution
$F=2 x^{2}-3 x-2$
$\frac{d F}{d x}=4 x-3<0$
$x<3 / 4$ for stable equilibrium
$x>3 / 4$ for unstable equilibrium
For stable $F=0$
$2 x^{2}-3 x-2=0$
$2 x^{2}-4 x+x-2=0$
$2 x(x-2)+1(x-2)=0$
$(2 x+1)(x-2)=0$
$x=-\frac{1}{2},$
Standard 11
Physics
Similar Questions
normal