If $A = \{ x:x$ is a natural number $\} ,B = \{ x:x$ is an even natural number $\} $ $C = \{ x:x$ is an odd natural number $\} $ and $D = \{ x:x$ is a prime number $\} ,$ find
$A \cap C$
$A = \{ x:x$ is a natural number $\} = \{ 1,2,3,4,5 \ldots \} $
$B = \{ x:x$ is an even natural number $\} = \{ 2,4,6,8 \ldots \} $
$C = \{ x:x$ is an odd natural number $\} = \{ 1,3,5,7,9 \ldots \} $
$D = \{ x:x$ is a primenumber $\} = \{ 2,3,5,7 \ldots \}$
$A \cap C = \{ x:x$ is an odd natural number $\} = C$
If $A, B, C$ are three sets, then $A \cap (B \cup C)$ is equal to
Let $A$ and $B$ be two sets. Then
Which of the following pairs of sets are disjoint
$\{ x:x$ is an even integer $\} $ and $\{ x:x$ is an odd integer $\} $
State whether each of the following statement is true or false. Justify you answer.
$\{2,6,10,14\}$ and $\{3,7,11,15\}$ are disjoint sets.
If $A=\{1,2,3,4\}, B=\{3,4,5,6\}, C=\{5,6,7,8\}$ and $D=\{7,8,9,10\} ;$ find
$A \cup B$