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2. Polynomials
easy
જો $p(x)=x^{2}-2 \sqrt{2} x+1,$ હોય, તો $p(2 \sqrt{2})$ =..........
A
$0$
B
$1$
C
$4 \sqrt{2}$
D
$8 \sqrt{2}+1$
Solution
We have $p(x)=x^{2}-2 \sqrt{2}x-1$
$\therefore \quad p(2 \sqrt{2})=(2 \sqrt{2})^{2}-2 \sqrt{2}(2 \sqrt{2}+1)$
$=8-8+1$
$=1$
Hence, $(b)$ is the correct answer.
Standard 9
Mathematics
