If θ is angle between velocity and acceleration of a particle moving on a circular path with decrea

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3-2.Motion in Plane

easy

If $\theta$ is angle between the velocity and acceleration of a particle moving on a circular path with decreasing speed, then .........

A$\theta=90^{\circ}$

B$0^{\circ} < \theta < 90^{\circ}$

C$90^{\circ} < \theta < 180^{\circ}$

D$0^{\circ} \leq \theta \leq 180^{\circ}$

Solution

(c)
$\theta$ between $v$ and $Q$ is
$90^{\circ} < \theta < 180^{\circ}$

Standard 11

Physics

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