If $A$ and $B$ are sets, then $A \cap (B -A)$ is
$\phi $
$A$
$B$
None of these
(a) $A \cap (B – A) = \phi $, $[\because x \in B – A \Rightarrow x\not \in A]$.
If $A = \{x : x$ is a multiple of $4\}$ and $B = \{x : x$ is a multiple of $6\}$ then $A \cap B$ consists of all multiples of
State whether each of the following statement is true or false. Justify you answer.
$\{a, e, i, o, u\}$ and $\{a, b, c, d\}$ are disjoint sets.
$\{2,3,4,5\}$ and $\{3,6\}$ are disjoint sets.
If $\mathrm{R}$ is the set of real numbers and $\mathrm{Q}$ is the set of rational numbers, then what is $\mathrm{R – Q} ?$
Let $A$ and $B$ be two sets in the universal set. Then $A – B$ equals
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