Let $A$ and $B$ be two sets in the universal set. Then $A - B$ equals
$A \cap {B^c}$
${A^c} \cap B$
$A \cap B$
None of these
(a) It is obvious.
Let $A$ and $B$ be subsets of a set $X$. Then
$A$ and $B$ are two subsets of set $S$ = $\{1,2,3,4\}$ such that $A\ \cup \ B$ = $S$ , then number of ordered pair of $(A, B)$ is
If $A=\{3,6,9,12,15,18,21\}, B=\{4,8,12,16,20\},$ $C=\{2,4,6,8,10,12,14,16\}, D=\{5,10,15,20\} ;$ find
$A-C$
If $A =$ [$x:x$ is a multiple of $3$] and $B =$ [$x:x$ is a multiple of $5$], then $A -B$ is ($\bar A$ means complement of $A$)
If $A, B$ and $C$ are non-empty sets, then $(A -B) \cup (B -A)$ equals
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