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1.Set Theory
medium
If $A = \{x : x$ is a multiple of $4\}$ and $B = \{x : x$ is a multiple of $6\}$ then $A \cap B$ consists of all multiples of
A
$16$
B
$12$
C
$8$
D
$4$
Solution
(b) $A = \{ 4,\,8,\,12,\,16,\,20,\,24,\,…..\} $
$B = \{ 6,\,12,\,18,\,24,\,30,\,….\} $
$\therefore A \cap B = \{ 12,\,24,\,….\} = \{x : x$ is a multiple of $12\}.$
Standard 11
Mathematics
