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2.Relations and Functions
easy
જો $n(A) = 4$, $n(B) = 3$, $n(A \times B \times C) = 24$, તો $n(C) = $
A
$288$
B
$1$
C
$12$
D
$2$
Solution
(d) $n(A) = 4$, $n(B) = 3$
$n(A) \times n(B) \times n(C) = n(A \times B \times C)$
$4 \times 3 \times n(C) = 24$ ==> $n(C) = {{24} \over {12}} = 2$.
Standard 11
Mathematics
