If $\oint_s \vec{E} \cdot \overrightarrow{d S}=0$ over a surface, then:
the electric field inside the surface is necessarily uniform.
the number of flux lines entering the surface must be equal to the number of flux lines leaving it.
the magnitude of electric field on the surface is constant.
all the charges must necessarily be inside the surface.
$(a)$ An electrostatic field line is a continuous curve. That is, a field line cannot have sudden breaks. Why not?
$(b)$ Explain why two field lines never cross each other at any point?
Consider the charge configuration and spherical Gaussian surface as shown in the figure. When calculating the flux of the electric field over the spherical surface the electric field will be due to
Linear charge density of wire is $8.85\,\mu C/m$ . Radius and height of the cylinder are $3\,m$ and $4\,m$ . Then find the flux passing through the cylinder
A point charge $+Q$ is positioned at the centre of the base of a square pyramid as shown. The flux through one of the four identical upper faces of the pyramid is
A charge $Q$ is placed at a distance $a/2$ above the centre of the square surface of edge $a$ as shown in the figure. The electric flux through the square surface is