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1.Set Theory
medium
જો ${N_a} = \{ an:n \in N\} ,$ તો ${N_3} \cap {N_4} = $
A
${N_7}$
B
${N_{12}}$
C
${N_3}$
D
${N_4}$
Solution
(b) ${N_3} \cap {N_4} = \{ 3,\,6,\,9,\,12,15……\} \cap \{ 4,\,8,\,12,\,16,\,20,…..\} $
$= \{12, 24, 36……\} =$ ${N_{12}}$.
Trick : ${N_3} \cap {N_4} = {N_{12}}$
[ $\because $ $3, 4$ are relatively prime numbers].
Standard 11
Mathematics
