If ${\log _5}a.{\log _a}x = 2,$then $x$ is equal to
$125$
${a^2}$
$25$
None of these
(c) ${\log _5}a.{\log _a}x = 2$ $\Rightarrow $ ${\log _5}x = 2$
$ \Rightarrow $ $x = {5^2} = 25$.
The value of ${(0.05)^{{{\log }_{_{\sqrt {20} }}}(0.1 + 0.01 + 0.001 + ……)}}$ is
$7\log \left( {{{16} \over {15}}} \right) + 5\log \left( {{{25} \over {24}}} \right) + 3\log \left( {{{81} \over {80}}} \right)$ is equal to
If $a = {\log _{24}}12,\,b = {\log _{36}}24$ and $c = {\log _{48}}36,$ then $1+abc$ is equal to
The number ${\log _2}7$ is
The number of real values of the parameter $k$ for which ${({\log _{16}}x)^2} – {\log _{16}}x + {\log _{16}}k = 0$ with real coefficients will have exactly one solution is
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