જો x = {2^{1/3}} - {2^{ - 1/3}}, તો 2{x^3} + 6x =

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Basic of Logarithms

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જો $x = {2^{1/3}} - {2^{ - 1/3}},$ તો $2{x^3} + 6x = $

A

$1$

B

$2$

C

$3$

D

એકપણ નહીં

Solution

(c) $x = {2^{1/3}} – {2^{ – 1/3}}$

$ \Rightarrow $${x^3} = 2 – {2^{ – 1}} – {3.2^{1/3}}{.2^{ – 1/3}}({2^{1/3}} – {2^{ – 1/3}})$

$ \Rightarrow $${x^3} = 2 – {1 \over 2} – 3x$ ==> ${x^3} + 3x = {3 \over 2}$

$\therefore 2{x^3} + 6x = 3$.

Standard 11

Mathematics

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