If $\varepsilon_0$ is the permittivity of free space and $E$ is the electric field, then $\varepsilon_0 E^2$ has the dimensions
If $\varepsilon_0$ is the permittivity of free space and $E$ is the electric field, then $\varepsilon_0 E^2$ has the dimensions
- [JEE MAIN 2024]
- A
$\left[\mathrm{M}^0 \mathrm{~L}^{-2} \mathrm{TA}\right]$
- B
$\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right]$
- C
$\left[\mathrm{M}^{-1} \mathrm{~L}^{-3} \mathrm{~T}^4 \mathrm{~A}^2\right]$
- D
$\left[\mathrm{M} \mathrm{L}^2 \mathrm{~T}^{-2}\right]$
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