Gujarati
8. Sequences and Series
easy

If ${\log _x}a,\;{a^{x/2}}$ and ${\log _b}x$ are in $G.P.$, then $x = $

A

$ - \log ({\log _b}a)$

B

$ - {\log _a}({\log _a}b)$

C

${\log _a}({\log _e}a) - {\log _a}({\log _e}b)$

D

${\log _a}({\log _e}b) - {\log _a}({\log _e}a)$

Solution

(c) Obviously ${({a^{x/2}})^2} = {\log _x}a\;.\;{\log _b}x = {\log _b}a$

$ \Rightarrow $${a^x} = {\log _b}a$

$ \Rightarrow $$x = {\log _a}({\log _b}a)$

$ \Rightarrow $$x = {\log _a}\left( {\frac{{{{\log }_e}a}}{{{{\log }_e}b}}} \right) = {\log _a}({\log _e}a) – {\log _a}({\log _e}b)$.

Standard 11
Mathematics

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