- Home
- Standard 11
- Mathematics
8. Sequences and Series
easy
If ${\log _x}a,\;{a^{x/2}}$ and ${\log _b}x$ are in $G.P.$, then $x = $
A
$ - \log ({\log _b}a)$
B
$ - {\log _a}({\log _a}b)$
C
${\log _a}({\log _e}a) - {\log _a}({\log _e}b)$
D
${\log _a}({\log _e}b) - {\log _a}({\log _e}a)$
Solution
(c) Obviously ${({a^{x/2}})^2} = {\log _x}a\;.\;{\log _b}x = {\log _b}a$
$ \Rightarrow $${a^x} = {\log _b}a$
$ \Rightarrow $$x = {\log _a}({\log _b}a)$
$ \Rightarrow $$x = {\log _a}\left( {\frac{{{{\log }_e}a}}{{{{\log }_e}b}}} \right) = {\log _a}({\log _e}a) – {\log _a}({\log _e}b)$.
Standard 11
Mathematics