If alpha { = ^m}{C_2}, then ^alpha {C_2}is eq | vedclass

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Question

(d) $\alpha { = ^m}{C_2} \Rightarrow \alpha = \frac{{m(m - 1)}}{2}$

$	herefore $$^\alpha {C_2}{ = ^{m(m - 1)/2}}{C_2} = \frac{1}{2}.\frac{{m(m - 1

Vedclass · Accepted Answer

$3\;.{\;^{m + 1}}{C_4}$

Vedclass · Answer

(d) $\alpha { = ^m}{C_2} \Rightarrow \alpha = \frac{{m(m - 1)}}{2}$

$	herefore $$^\alpha {C_2}{ = ^{m(m - 1)/2}}{C_2} = \frac{1}{2}.\frac{{m(m - 1)}}{2}\left\{ {\frac{{m(m - 1)}}{2} - 1} ight\}$

$ = \frac{1}{8}m(m - 1)(m - 2)(m + 1)$

$ = \frac{1}{8}(m + 1)\;m(m - 1)(m - 2) = 3\;.{\;^{m + 1}}{C_4}$

If $\alpha { = ^m}{C_2}$, then $^\alpha {C_2}$is equal to

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