3 and 4 .Determinants and Matrices
easy

यादि  $A = [1\,\,2\,{\rm{ }}3]$ ओर $B = \left[ {\begin{array}{*{20}{c}}{ - 5}&4&0\\0&2&{ - 1}\\1&{ - 3}&2\end{array}} \right]$, तो $AB = $

A

$\left[ {\begin{array}{*{20}{c}}{ - 5}&4&0\\0&4&{ - 2}\\3&{ - 9}&6\end{array}} \right]$

B

$\left[ \begin{array}{l}3\\1\\1\end{array} \right]$

C

$\left[ {\begin{array}{*{20}{c}}{ - 2}&{ - 1}&4\end{array}} \right]$

D

$\left[ {\begin{array}{*{20}{c}}{ - 5}&8&0\\0&4&{ - 3}\\1&{ - 6}&6\end{array}} \right]$

Solution

(c) $AB = [1\,\,2\,\,3]\,\left[ {\begin{array}{*{20}{c}}{ – 5}&4&0\\0&2&{ – 1}\\1&{ – 3}&2\end{array}} \right] = [ – 2\,\, – 1\,\,\,4]$.

Standard 12
Mathematics

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