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3 and 4 .Determinants and Matrices
easy
यदि $A = \left[ {\begin{array}{*{20}{c}}2&0&0\\0&2&0\\0&0&2\end{array}} \right]$तो ${A^5} = $
A
$5A$
B
$10A$
C
$16A$
D
$32A$
Solution
(c) $A = \left[ {\begin{array}{*{20}{c}}2&0&0\\0&2&0\\0&0&2\end{array}} \right]\, \Rightarrow {A^5} = \left[ {\begin{array}{*{20}{c}}{{2^5}}&0&0\\0&{{2^5}}&0\\0&0&{{2^5}}\end{array}} \right] = {2^4}\left[ {\begin{array}{*{20}{c}}2&0&0\\0&2&0\\0&0&2\end{array}} \right]$ $ = 16A$.
Standard 12
Mathematics