3 and 4 .Determinants and Matrices
easy

यदि $A = \left[ {\begin{array}{*{20}{c}}0&1\\0&0\end{array}} \right],I$ कोटि $2$ का तत्समक आव्यूह है और $a, b$ स्वेच्छ नियतांक हैं, तो ${(aI + bA)^2}$=

A

${a^2}I + abA$

B

${a^2}I + 2abA$

C

${a^2}I + {b^2}A$

D

इनमें से कोई नहीं

Solution

(b) ${(aI + bA)^2} = \left[ {\begin{array}{*{20}{c}}a&b\\0&a\end{array}} \right]\,\left[ {\begin{array}{*{20}{c}}a&b\\0&a\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}{{a^2}}&{2ab}\\0&{{a^2}}\end{array}} \right] = {a^2}I + 2abA$.

Standard 12
Mathematics

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