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3 and 4 .Determinants and Matrices
easy
यदि $\left[ {\begin{array}{*{20}{c}}x&0\\1&y\end{array}} \right] + \left[ {\begin{array}{*{20}{c}}{ - 2}&1\\3&4\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}3&5\\6&3\end{array}} \right] - \left[ {\begin{array}{*{20}{c}}2&4\\2&1\end{array}} \right]$, तो
A
$x = - 3,y = - 2$
B
$x = 3,y = - 2$
C
$x = 3,y = 2$
D
$x = - 3,y = 2$
Solution
चूकि $x – 2 = 3 – 2 \Rightarrow x = 3$
तथा $y + 4 = 3 – 1 \Rightarrow y = – 2$.
Standard 12
Mathematics
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