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3 and 4 .Determinants and Matrices
easy
જો $A = \left[ {\begin{array}{*{20}{c}}1&0\\2&0\end{array}} \right],B = \left[ {\begin{array}{*{20}{c}}0&0\\1&{12}\end{array}} \right]$, તો
A
$AB = O,BA = O$
B
$AB = O,BA \ne O$
C
$AB \ne O,BA = O$
D
$AB \ne O,BA \ne O$
Solution
(b) $AB = \,\left[ {\begin{array}{*{20}{c}}1&0\\2&0\end{array}\,} \right]\,\left[ {\begin{array}{*{20}{c}}0&0\\1&{12}\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}0&0\\0&0\end{array}} \right] = O$
while $BA = \left[ {\begin{array}{*{20}{c}}0&0\\1&{12}\end{array}} \right]\,\left[ {\begin{array}{*{20}{c}}1&0\\2&0\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}0&0\\{25}&0\end{array}} \right]\, \ne O$.
Standard 12
Mathematics
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