If tan theta - sqrt 2 sec theta = sqrt 3 , th | vedclass

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Question

(d) $	an 	heta - \sqrt 2 \sec 	heta = \sqrt 3$

$\Rightarrow \sin 	heta - \sqrt 3 \cos 	heta = \sqrt 2 $

$ \Rightarrow $ $\sin \left( {	het

Vedclass · Accepted Answer

$n\pi + {( - 1)^n}\frac{\pi }{4} + \frac{\pi }{3}$

Vedclass · Answer

(d) $	an 	heta - \sqrt 2 \sec 	heta = \sqrt 3$

$\Rightarrow \sin 	heta - \sqrt 3 \cos 	heta = \sqrt 2 $

$ \Rightarrow $ $\sin \left( {	heta - \frac{\pi }{3}} ight) = \sin \frac{\pi }{4}$

$\Rightarrow 	heta = n\pi + {( - 1)^n}\frac{\pi }{4} + \frac{\pi }{3}$.

If $\tan \theta - \sqrt 2 \sec \theta = \sqrt 3 $, then the general value of $\theta $ is

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