Trigonometrical Equations
easy

The value of $\theta $ in between ${0^o}$ and ${360^o}$ and satisfying the equation $\tan \theta + \frac{1}{{\sqrt 3 }} = 0$ is equal to

A

$\theta = {150^o}$ and ${300^o}$

B

$\theta = {120^o}$ and ${300^o}$

C

$\theta = {60^o}$ and ${240^o}$

D

$\theta = {150^o}$ and ${330^o}$

Solution

(d) We have, $\tan \theta + \frac{1}{{\sqrt 3 }} = 0$ or $\tan \theta = – \frac{1}{{\sqrt 3 }}$ 

$\because$ $\theta $ lies in between $0^\circ $ and $360^\circ $

$\therefore $ $\theta = 150^\circ $ and $330^\circ $.

Standard 11
Mathematics

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