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Trigonometrical Equations
easy
The value of $\theta $ in between ${0^o}$ and ${360^o}$ and satisfying the equation $\tan \theta + \frac{1}{{\sqrt 3 }} = 0$ is equal to
A
$\theta = {150^o}$ and ${300^o}$
B
$\theta = {120^o}$ and ${300^o}$
C
$\theta = {60^o}$ and ${240^o}$
D
$\theta = {150^o}$ and ${330^o}$
Solution
(d) We have, $\tan \theta + \frac{1}{{\sqrt 3 }} = 0$ or $\tan \theta = – \frac{1}{{\sqrt 3 }}$
$\because$ $\theta $ lies in between $0^\circ $ and $360^\circ $
$\therefore $ $\theta = 150^\circ $ and $330^\circ $.
Standard 11
Mathematics
