If (4, 0) and (-4, 0) be vertices and (6, 0) and (-6, 0) be foci of a hyperbola, then its eccentrici

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10-2. Parabola, Ellipse, Hyperbola

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If $(4, 0)$ and $(-4, 0)$ be the vertices and $(6, 0)$ and $(-6, 0)$ be the foci of a hyperbola, then its eccentricity is

A

$5\over2$

B

$2$

C

$3\over2$

D

$\sqrt 2 $

Solution

(c) Vertices $( \pm 4,\,0) \equiv ( \pm a,\,0)$

==> $a = 4$

Foci $( \pm 6,\,0) \equiv ( \pm ae,\,0)$

==> $e = \frac{6}{4} = \frac{3}{2}$.

Standard 11

Mathematics

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