If $A$ and $B$ are mutually exclusive events, then the value of $P (A$ or $B$) is
$0$
$-1$
$1$
None of these
(c) It is obvious.
The probability that a marksman will hit a target is given as $1/5$. Then his probability of at least one hit in $10$ shots, is
The probability of a sure event is
Two card are drawn successively with replacement from a pack of $52$ cards. The probability of drawing two aces is
One card is drawn from a pack of $52$ cards. The probability that it is a king or diamond is
If $A$ and $B$ are two independent events such that $P\,(A \cap B') = \frac{3}{{25}}$ and $P\,(A' \cap B) = \frac{8}{{25}},$ then $P(A) = $
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