If $A$ and $B$ are any two events, then $P(A \cup B) = $
$P(A) + P(B)$
$P(A) + P(B) + P(A \cap B)$
$P(A) + P(B) - P(A \cap B)$
$P(A)\,\,.\,\,P(B)$
(c) It is a fundamental concept.
The probabilities that $A$ and $B$ will die within a year are $p$ and $q$ respectively, then the probability that only one of them will be alive at the end of the year is
If the odds in favour of an event be $3 : 5$, then the probability of non-occurrence of the event is
Probability of solving specific problem independently by $A$ and $B$ are $\frac{1}{2}$ and $\frac{1}{3}$ respectively. If both try to solve the problem independently, find the probability that exactly one of them problem
For three events $A,B $ and $C$ ,$P ($ Exactly one of $A$ or $B$ occurs$)\, =\, P ($ Exactly one of $C$ or $A$ occurs $) =$ $\frac{1}{4}$ and $P ($ All the three events occur simultaneously $) =$ $\frac{1}{16}$ Then the probability that at least one of the events occurs is :
True statement $A$ and true statement $B$ are two independent events of an experiment.Let $P\left( A \right) = 0.3$ , $P\left( {A \vee B} \right) = 0.8$ then $P\left( {A \to B} \right)$ is (where $P(X)$ denotes probability that statement $X$ is true statement)
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