A die is loaded in such a way that each odd number is twice as likely to occur as each even number.

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14.Probability

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A die is loaded in such a way that each odd number is twice as likely to occur as each even number. If $E$ is the event that a number greater than or equal to $4$ occurs on a single toss of the die then $P(E)$ is equal to

A

$\frac{4}{9}$

B

$\frac{2}{3}$

C

$\frac{1}{3}$

D

$\frac{1}{2}$

Solution

Prob. of even $n \circ=p$

Prob. of odd no $=2 p$

$3(2 p)+3(p)=1 \Rightarrow p=\frac{1}{9}$

Req. prob $=\frac{4}{9}$

Standard 11

Mathematics

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