If X = { {4^n} - 3n - 1:n ∈ N} and Y = { 9(n - 1):n ∈ N} , then X cup Y = . . . . .

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1.Set Theory

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If $X = \{ {4^n} - 3n - 1:n \in N\} $ and $Y = \{ 9(n - 1):n \in N\} ,$ then $X \cup Y$ = . . . . .

A

$X$

B

$Y$

C

$N$

D

None of these

(JEE MAIN-2014)

Solution

$ x=\left\{4^{n}-3 n-1\right\} $

$=\{0,9,54, \ldots\} $

$ Y =\{9(n-1)\} $

$=\{0,9,18,27, \ldots\} $

$ \therefore X U Y=Y $

Standard 11

Mathematics

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