Let $A=\{1,2,3,4,5,6\}, B=\{2,4,6,8\} .$ Find $A-B$ and $B-A$

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We have, $A-B=\{1,3,5\},$ since the elements $1,3,5$ belong to $A$ but not to $B$ and $B - A =\{8\},$ since the element $8$ belongs to $B$ and not to $A$. We note that $A-B \neq B-A$

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