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3 and 4 .Determinants and Matrices
medium
यदि $P =\left[\begin{array}{lll}1 & \alpha & 3 \\ 1 & 3 & 3 \\ 2 & 4 & 4\end{array}\right] 3 \times 3$ आव्यूह $A$ का सहखण्डज है और $| A |=4$ तो $\alpha$ का मान है
A
$4$
B
$11$
C
$5$
D
$0$
(JEE MAIN-2013)
Solution
$|P|=1(12-12)-\alpha(4-6)+3(4-6)$
$=2 \alpha-6$
$|P|=|A|^{2}=16$
$2 \alpha-6=16$
$\alpha=11.$
Standard 12
Mathematics
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