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3 and 4 .Determinants and Matrices
medium
જો $P = \left[ {\begin{array}{*{20}{c}}1&\alpha &3\\1&3&3\\2&4&4\end{array}} \right]$ એ $3×3 $ શ્રેણિક $A$ નો સહઅવયવજ હોય અને $ |A|=4$ તો $\alpha $ મેળવો.
A
$4$
B
$11$
C
$5$
D
$0$
(JEE MAIN-2013)
Solution
$|P|=1(12-12)-\alpha(4-6)+3(4-6)$
$=2 \alpha-6$
$|P|=|A|^{2}=16$
$2 \alpha-6=16$
$\alpha=11.$
Standard 12
Mathematics
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