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3 and 4 .Determinants and Matrices
normal
If $A$ is a square matrix of order $3$ with $|A| = 2$, then the value of $|(A -A^T)^5| + |(A^T -A)^3|$ is-
A
$24$
B
$16$
C
$0$
D
$8$
Solution
$(A^T -A)$ and $(A -A^T)$
Skew symmetric mat. of $(3 × 3)$ order
and $|A^T -A| = |A -A^T| = 0$
Standard 12
Mathematics