3 and 4 .Determinants and Matrices
normal

If $A$ is a square matrix of order $3$ with $|A| = 2$, then the value of $|(A -A^T)^5| + |(A^T -A)^3|$ is-

A

$24$

B

$16$

C

$0$

D

$8$

Solution

$(A^T -A)$ and $(A -A^T)$
Skew symmetric mat. of $(3 × 3)$ order
and $|A^T -A| = |A -A^T| = 0$

Standard 12
Mathematics

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