Gujarati
Hindi
10-2. Parabola, Ellipse, Hyperbola
normal

If $\frac{{{{\left( {3x - 4y - z} \right)}^2}}}{{100}} - {\frac{{\left( {4x + 3y - 1} \right)}}{{225}}^2} = 1$ then
length of latusrectum of hyperbola is

A

$4.5$

B

$\frac{40}{3}$

C

$9$

D

$\frac{8}{3}$

Solution

$\frac{\left(\frac{3 \mathrm{x}-4 \mathrm{y}-1}{5}\right)^{2}}{4}-\frac{\left(\frac{4 \mathrm{x}+3 \mathrm{y}-1}{5}\right)^{2}}{9}=1$

length of latus rectum $=\frac{2 b^{2}}{a}=\frac{2.9}{2}=9$

Standard 11
Mathematics

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