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10-2. Parabola, Ellipse, Hyperbola
normal
If $\frac{{{{\left( {3x - 4y - z} \right)}^2}}}{{100}} - {\frac{{\left( {4x + 3y - 1} \right)}}{{225}}^2} = 1$ then
length of latusrectum of hyperbola is
A
$4.5$
B
$\frac{40}{3}$
C
$9$
D
$\frac{8}{3}$
Solution
$\frac{\left(\frac{3 \mathrm{x}-4 \mathrm{y}-1}{5}\right)^{2}}{4}-\frac{\left(\frac{4 \mathrm{x}+3 \mathrm{y}-1}{5}\right)^{2}}{9}=1$
length of latus rectum $=\frac{2 b^{2}}{a}=\frac{2.9}{2}=9$
Standard 11
Mathematics