If a body of mass 200, g falls from a height 200 ,m and its total P.E. is converted into K.E. at poi

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5.Work, Energy, Power and Collision

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If a body of mass $200\, g$ falls from a height $200 \,m$ and its total $P.E.$ is converted into $K.E.$ at the point of contact of the body with earth surface, then what is the decrease in $P.E.$ of the body at the contact $(g = 10\,m/{s^2})$ ............ $\mathrm{J}$

A

$200$

B

$400$

C

$600$

D

$900 $

Solution

(b)$\Delta U = mgh = 0.2 \times 10 \times 200$$= 400 \,J$

Gain in $K.E. =$ decrease in $P.E. = 400 \,J.$

Standard 11

Physics

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