- Home
- Standard 11
- Mathematics
14.Probability
medium
यदि एक लीप वर्ष को यादृच्छया चुना गया हो तो इसकी क्या प्रायिकता है कि उस वर्ष में $53$ मंगलवार होंगे?
A
$\frac{2}{7}$
B
$\frac{2}{7}$
C
$\frac{2}{7}$
D
$\frac{2}{7}$
Solution
In a leap year, there are $366$ days i.e., $52$ weeks and $2$ days.
In $52$ weeks, there are $52$ Tuesdays.
Therefore, the probability that the leap year will contain $53$ Tuesday is equal to the probability that the remaining $2$ days will be Tuesdays.
The remaining $2$ days can be
Monday and Tuesday
Tuesday and Wednesday
Wednesday and Thursday
Thursday and Friday
Friday and Saturday
Saturday and Sunday
Sunday and Monday
Total number of cases $=7$
Favorable cases $=2$
Probability that a leap year will have $53$ Tuesdays $=\frac{2}{7}$
Standard 11
Mathematics