If a proton is projected in a direction perpendicular to a uniform magnetic field with velocity $v$ and an electron is projected along the lines of force, what will happen to proton and electron
The electron will travel along a circle with constant speed and the proton will move along a straight line
Proton will move in a circle with constant speed and there will be no effect on the motion of electron
There will not be any effect on the motion of electron and proton
The electron and proton both will follow the path of a parabola
A negative charge is coming towards the observer. The direction of the magnetic field produced by it will be (as seen by observer)
A proton, a deuteron and an $\alpha-$particle with same kinetic energy enter into a uniform magnetic field at right angle to magnetic field. The ratio of the radii of their respective circular paths is
When a charged particle enters a uniform magnetic field its kinetic energy
A particle moving with velocity v having specific charge $(q/m)$ enters a region of magnetic field $B$ having width $d=\frac{{3mv}}{{5qB}}$ at angle $53^o$ to the boundary of magnetic field. Find the angle $\theta$ in the diagram......$^o$
A homogeneous electric field $E$ and a uniform magnetic field $\mathop B\limits^ \to $ are pointing in the same direction. A proton is projected with its velocity parallel to $\mathop E\limits^ \to $. It will