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1. Electric Charges and Fields
easy
If a spherical conductor comes out from the closed surface of the sphere then total flux emitted from the surface will be
A
$\frac{1}{{{\varepsilon _0}}} \times $ (the charge enclosed by surface)
B
${\varepsilon _0} \times $ (charge enclosed by surface)
C
$\frac{1}{{4\pi {\varepsilon _0}}} \times $ (charge enclosed by surface)
D
$0$
Solution
(a) ${\varphi _{surface}} = \frac{1}{{{\varepsilon _0}}}({Q_{enclosed}})$
Standard 12
Physics
