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5.Work, Energy, Power and Collision
normal
If a spring extends by $x$ on loading then energy stored by the spring is ($T$ is tension in spring, $K$ is spring constant)
A
$\frac{{{T^2}}}{{2x}}$
B
$\frac{{{T^2}}}{{2K}}$
C
$\frac{{2K}}{{{T^2}}}$
D
$\frac{{2{T^2}}}{K}$
Solution
Energy stored in spring
$\mathrm{U}=1 / 2 \mathrm{Kx}^{2} \quad$ as $\quad \mathrm{T}=\mathrm{Kx}$
$=1 / 2 \mathrm{K} \frac{\mathrm{T}^{2}}{\mathrm{K}^{2}} \quad \mathrm{U}=1 / 2 \frac{\mathrm{T}^{2}}{\mathrm{K}}$
Standard 11
Physics
