6.Permutation and Combination
normal

If all the letters of the word $'GANGARAM'$ be arranged, then number of words in which exactly two vowels are together but no two $'G'$ occur together is-

A

$1320$

B

$1560$

C

$1800$

D

$1740$

Solution

use AA, A in gaps for both cases

so, number of ways

$ = \frac{{5!}}{{2!}}{.^6}{C_2}.2! – 4!.{\,^5}{C_2}.2! = 1320$

Standard 11
Mathematics

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