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6.Permutation and Combination
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If all the letters of the word $'GANGARAM'$ be arranged, then number of words in which exactly two vowels are together but no two $'G'$ occur together is-
A
$1320$
B
$1560$
C
$1800$
D
$1740$
Solution

use AA, A in gaps for both cases
so, number of ways
$ = \frac{{5!}}{{2!}}{.^6}{C_2}.2! – 4!.{\,^5}{C_2}.2! = 1320$
Standard 11
Mathematics
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