The number of ways in which $10$ persons can go in two boats so that there may be $5 $ on each boat, supposing that two particular persons will not go in the same boat is
The number of ways in which $10$ persons can go in two boats so that there may be $5 $ on each boat, supposing that two particular persons will not go in the same boat is
- A
$\frac{1}{2}{(^{10}}{C_5})$
- B
$2{(^8}{C_4})$
- C
$\frac{1}{2}{(^8}{C_5})$
- D
None of these
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