If atmospheric electric field is approximatel | vedclass

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Question

(a)

$E=150 \,V / m$

$R=6400 \,km$

Using Gauss' Law

$\Rightarrow E A=\frac{q}{\varepsilon_0}$

$\Rightarrow 150\left(4 \pi\left(6400

Vedclass · Accepted Answer

$6.8 	imes 10^5$

Vedclass · Answer

(a)

$E=150 \,V / m$

$R=6400 \,km$

Using Gauss' Law

$\Rightarrow E A=\frac{q}{\varepsilon_0}$

$\Rightarrow 150\left(4 \pi\left(6400 	imes 10^3ight)^2ight)=\frac{q}{\varepsilon_0}$

$q=150 	imes 4 \pi 	imes\left(6400 	imes 10^3ight)^2 	imes 8.854 	imes 10^{-12}$

$q=6.8 	imes 10^5 \,C$

If atmospheric electric field is approximately $150 \,volt / m$ and radius of the earth is $6400 \,km$, then the total charge on the earth's surface is .......... coulomb

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