If e is the electronic charge, c is the speed | vedclass

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Question

$F =\frac{1}{4 \pi \epsilon_{0}} \frac{ e ^{2}}{ r ^{2}}$
$E =\frac{ hc }{\lambda}$
$\left[\frac{ e ^{2}}{4 \pi \varepsilon_{0}} 	imes \frac{1}{ hc

Vedclass · Accepted Answer

$\left[ M ^{0} L ^{0} T ^{0}\right]$

Vedclass · Answer

$F =\frac{1}{4 \pi \epsilon_{0}} \frac{ e ^{2}}{ r ^{2}}$
$E =\frac{ hc }{\lambda}$
$\left[\frac{ e ^{2}}{4 \pi \varepsilon_{0}} 	imes \frac{1}{ hc }ight]=\frac{ Fr ^{2}}{ E \lambda}=\left( M ^{0} L ^{0} T ^{0}ight)$

If e is the electronic charge, $c$ is the speed of light in free space and $h$ is Planck's constant, the quantity $\frac{1}{4 \pi \varepsilon_{0}} \frac{| e |^{2}}{h c}$ has dimensions of .......

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