1.Relation and Function
normal

If for the function $f(x) = \frac{1}{4}{x^2} + bx + 10$ ; $f\left( {12 - x} \right) = f\left( x \right)\,\forall \,x\, \in \,R$ , then the value of $'b'$ is 

A

$-3$

B

$3$

C

$6$

D

$-6$

Solution

Graph is
symmetric about $x = 6$

$ – 2b = 6 \Rightarrow b =  – 3$

Standard 12
Mathematics

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