1.Relation and Function
easy

If $y = f(x) = \frac{{ax + b}}{{cx - a}}$, then $x$ is equal to

A

$1/f(x)$

B

$1/f(y)$

C

$yf(x)$

D

$f(y)$

Solution

(d) $y = \frac{{ax + b}}{{cx – a}}$

$⇒ x(cy – a) = b + ay$ 

$⇒ x = \frac{{ay + b}}{{cy – a}} = f(y)$.

Standard 12
Mathematics

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