If half-life of a substance is 3.8, days and | vedclass

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(b) Number of half lives $n = \frac{{19}}{{3.8}} = 5;$

Now $\frac{N}{{{N_0}}} = {\left( {\frac{1}{2}} \right)^n}$

$ \Rightarrow \frac{N}{{10.38}

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$0.32 $

Vedclass · Answer

(b) Number of half lives $n = \frac{{19}}{{3.8}} = 5;$

Now $\frac{N}{{{N_0}}} = {\left( {\frac{1}{2}} ight)^n}$

$ \Rightarrow \frac{N}{{10.38}} = {\left( {\frac{1}{2}} ight)^5}$

$\Rightarrow N = 10.38 	imes {\left( {\frac{1}{2}} ight)^5}$$ = 0.32\,gm$

If half-life of a substance is $3.8\, days$ and its quantity is $10.38\, gm$. Then substance quantity remaining left after $19\, days$ will be ........$gm$

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