If half life of radium is 77 days. Its decay constant in day will be

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13.Nuclei

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If half life of radium is $77$ days. Its decay constant in day will be

A

$3 \times {10^{ - 13}}\, /day$

B

$9 \times {10^{ - 3}}\, /day$

C

$1 \times {10^{ - 3}}\, /day$

D

$6 \times {10^{ - 3}}\, /day$

Solution

(b) $\lambda = \frac{{0.693}}{{{T_{1/2}}}} = \frac{{0.693}}{{77}}$$ = 9 \times {10^{ – 3}}/day$.

Standard 12

Physics

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