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13.Nuclei
medium
A radioactive nucleus (initial mass number $A$ and atomic number $Z$ emits $3 \alpha$. - particles and $2$ positrons. The ratio of number of neutrons to that of protons in the final nucleus will be
A
$\frac{{A - Z - 4}}{{Z - 2}}$
B
$\frac{{A - Z - 8}}{{Z - 4}}$
C
$\frac{{A - Z - 4}}{{Z - 8}}$
D
$\frac{{A - Z - 12}}{{Z - 4}}$
(AIEEE-2010)
Solution
$_Z^AX{\xrightarrow{{{\text{A}} – 12}}_{Z – 8}}{\text{Y}} + 3_2^4{{\text{X}}_{\text{e}}} + _t^0e$
$\mathrm{A}-12-(\mathrm{Z}-8)$
$\therefore$ Required ratio $=\frac{A-Z-Y}{Z-8}$
Standard 12
Physics
