7.Gravitation
easy

If height of a satellite from the surface of earth is increased, then its

A

Potential energy will increase

B

Kinetic energy will decrease

C

Total energy will increase

D

All of these

Solution

(d)

For a satellite orbiting at height $h$ from earth,

$P.E=-\frac{G M_e m_s}{\left(R_e+h\right)}$

$K \cdot E =\frac{G M_\theta m_s}{2\left(R_\theta+h\right)}$

$T.E=-\frac{G M_e m_s}{2\left(R_\theta+h\right)}$

If $h$ is increased, $P.E$ increases (becomes less negative)

$K.E$ decreases

$T.E$ increases (becomes less negative)

Standard 11
Physics

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